Now, the Chapter on the Lunar Eclipse

original: "Atha Chandra-parva-adhikarah"

Multiply the daily motion of the planet by the elapsed or remaining days and divide by sixty original: "kharasa," a numerical code for 60; the result, when subtracted from or added to the planet's position, gives the true position.

In the southern hemisphere, the latitude decreases from the centers. || 3

The time elapsed in ghatis a unit of time equal to 24 minutes multiplied by the daily motion and divided by sixty gives the minutes of arc to be subtracted or added. 1. Thus, at the end of the lunar period the full moon, the Sun and Moon are calculated without the node Rahu.

When the Sun is in the northern hemisphere, the latitude is north; in the southern hemisphere, the latitude is south.

If the distance is within sixty-four degrees original: "khansha", a lunar eclipse is possible. Multiply those degrees by eleven and divide by two hundred and eleven to find the latitude. Subtract the Sun's position from the Moon's; if the remainder is six signs...

of the Sun The diameter is calculated starting from two digits angulas. The motion multiplied by two and divided by ten gives the diameter; the body of the Moon is similarly determined. The motion of the Moon divided by seven hundred and forty-two...

In a small eclipse. || 2

Lunar The diameter is thus declared. The lunar motion minus seven hundred and sixteen, divided by twenty-two and thirty-two original: "lochana-kara" and "dada", gives the diameter of Rahu itself. The Earth's shadow original: "bhubha" is the diameter of the Sun...

Otherwise, it is always less than the diameter of Rahu. I shall speak of the obscuration here and nowhere else. || 2

...minus the seventh part of the motion. What covers the Moon? In a lunar eclipse, the Earth's shadow is the obscurer and the Moon is the obscured. Calculate the half-sum of their diameters Manaikya-khanda: the combined radii of the shadow and the Moon.

Subtract the latitude from that; the result is the magnitude of the eclipse. When this obscured portion is subtracted from the diameter of the object to be eclipsed, the remainder is the clear portion. Add the half-sum of the diameters to the latitude, multiply by ten, and multiply by the obscured portion. The square root root of this, divided by sixty, gives the duration of the eclipse original: "sthiti" in ghatis and other units.