This library is built in the open.
If you spot an error, have a suggestion, or just want to say hello — we’d love to hear from you.

...with six arrows [he destroyed] the chariot, and with an equal number the horses; with one the flag-staff, with one the bow, and with one he cut off the head [of his enemy]. Arjuna let fly these arrows. 61.
Statement original: "nyāsaḥ": Root-Sum Root multiplier: 4. Part: 1/2. Visible quantity: 10. stain/erasure? By the rule "When indeed [the quantity] is diminished or increased" etc., there is produced:
Root multiplier: 8. Visible quantity: 20. And thus, by the calculation, the result the total number of arrows is 100.
62 The square root of half a swarm of bees went to a Malati jasmine; eight-ninths of the whole swarm [went to another spot]. One female bee, lured by the scent of a lotus at night, was trapped within it and hums [to her mate]. Tell me, dear one, the number of the swarm! 62.
Statement original: "nyāsaḥ": Here, eight-ninths of the quantity and the square root of half the quantity [are given]. The "visible" units are two the trapped bee and her mate outside. Thus, the layout: Root multiplier: 1/2. Visible: 2. The fraction of eight-ninths is set down. Therefore, by the rule "When indeed [the quantity] is diminished" etc., the calculation produces:
Root multiplier: 1/2. Visible quantity: 9/8.
From these, as before, the measure of the swarm is produced: the half-measure is 36, and the double the full swarm measure is 72.
A quantity which, when joined with twelve times its own square root and one-third of itself, becomes one hundred and twelve. Quickly find that [quantity]...