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E.
+ I say and declare that because fifty-two in such a deck original: "cartula"; here referring to a pack or set of cards cannot be divided into three equal parts, as five divides it and p p p p sixty, however, can evidently be divided into several equal parts. And thus the aliquot parts A mathematical term for a number that divides another exactly without a remainder; a divisor of the number sixty greatly exceed the aliquot parts of the number fifty-two. Even if a single unit is an aliquot part, no one plays alone, for this game is a certain kind of conflict which cannot happen with only one person. Two, however, are able to play; and in the first number [52], each will have 26 cards. In the second number [60], however, each will have 30. / Three in the first number—or in a game—cannot [play] by themselves unless some cards remain over; however, they can in the second, and each will have 20. / Four are able to play in both numbers: in the first number [52], each will have or many / 13. In the second [60], each will have 15. / In the first number, however, in a game where no more can be made, they play in greater numbers up to 13, unless some remain, where each will have 4. In the second number [60], five players will each have 12 cards; / 6 will each have 10; / 10 will each have 5 6 cards; / 12 persons will each have 5 cards; / fifteen will each have four; 1 / 20 persons will each have three cards; / 30 persons will each have two cards. In the first number [52], however, in the game rosuero? Possibly a specific name for a game or a scribal error for "of the deck" among 26 persons, each will have two cards. And so, from what has been said, it is clear that for the sake of convenience, so that no card remains left over among the players, it is better and more convenient to play with 60 cards than with 52. And let this be [sufficient] regarding the first reason; it is clear.