will be forced to pass into the vessel E. F. through the pipe M. N. X. O. from which the wine, which will be contained in that vessel, will be pushed out, and this will happen as many times as we pour water into the vessel, it being manifest that the body of the air is equal to that of the water, and likewise the wine, and if the bent pipe is not there, but only the channel S., the same will occur, provided the channel is not overcome by the violence of the water.

❧ TO FABRICATE A PIPE THAT FLOWS ❧

as much water and wine as we desire.

Theorema XXIV.

LET the empty vessel A. B. be either cylindrical in form or a rectangular parallelepiped, beside which let another vessel C. D., closed on all sides, be placed upon the same base; if it is cylindrical or a rectangular parallelepiped, it does not matter, provided that the base of the vessel A. B. is double that of the vessel C. D., since we wish the water to be double the wine. Then, beside this, upon the same base, let another vessel E. F. be placed, as in the figure, closed on all sides and very well soldered, into which wine is placed. And to these two vessels C. D. and E. F., let the tube G. H. K. be common, inclined at each end and perforated through their diaphragms internal partitions and very well soldered. Then, let there be in the vessel E. F. the bent pipe L. M. N., of which the inner leg is as far from the bottom of the vessel as is necessary for the effusion of the water. Let the other leg be bent in the vessel, as

A complex technical diagram shows three interconnected vessels (A-B, C-D, E-F) and an auxiliary vessel (O-X). A series of internal and external pipes (labeled G, H, K, L, M, N, S, T, P, R) connect the air spaces and liquid reservoirs. A bottom drainage pipe with a stopcock valve (V-Z) controls the flow. The system demonstrates fluid mechanics involving compressed air and the displacement of wine by water.

the figure demonstrates, and pass into another vessel O. X., outside of which, and below its bottom, and from the others, let the perforated pipe P. R. pass through the base common to them from the vessel O. X. to the vessel A. B. Furthermore, let the tube S. T. be placed in the vessels A. B. and C. D., which are pierced by it, and let the vessel A. B. have, at the bottom and a short distance from the floor, the small channel Y.; and let the small channels P. R. Y. enter the pipe V. Z., in which there is a key stopcock or faucet that closes it and holds it at our pleasure. Everything being done, and with the channel V. Z. closed by the key, if we put water into the vessel A. B., a part of it will go into the vessel C. D. through the tube S. T., and consequently it will drive out the air enclosed therein through the pipe G. H. K. into the vessel E. F., and this will push an equal amount of wine into the vessel O. X. through the tube L. M. N. Wherefore, having opened the channel V. Z. with the key, there will exit through it both the water poured into the vessel A. B. and the wine, which from outside the vessel O. X. through

the tube or pipe P. R. will be carried, whence we will have what was proposed. And once the humors fluids have flowed out of them, the vessels will return to being filled with air through the same channels or conduits.

❧ IF THERE IS WATER IN A VESSEL, AND IN IT ❧

a channel in which there is a key, and in said water an animal swims: make it so that as much water is taken from the vessel, the animal sprays as much wine from its mouth. Theor. XXV.

LET there be the water vessel A. B., in the bottom of which is the closed channel C., and in this water let the basin D. float, in which is the tube E. F. shaped into an animal. Then, beside said vessel, let the vessel G. H. filled with wine be placed, in which is the bent pipe K. L. M., one leg of which is in the vessel G. H., and the other enters into the tube E. F. If through the mouth M. we draw the wine, it will come into the tube E. F., nor will it stop until the surface of the wine that is in the vessel G. H. is leveled with that of the wine in the tube E. F. Let it be, therefore, that these are found on a straight line N. X. P., and in the tube let there be the small open channel R. Up to this point, the wine will not go out of it, but if through the channel C. we draw a cup of water, the basin D. will descend, and with it the tube E. F., so that the surface N. X. will become lower than the surface of the wine; wherefore, the leg of the bent pipe that is in the tube E. F. becoming lower, the wine will exit through the channel R., and this will happen as much and as many times as water is removed through the channel C., it being agreed that the animal will spray as much wine as the amount of water removed, whence one will have what was proposed above.

A diagram illustrates an automaton mechanism. A large circular vessel (A) filled with water contains a floating basin (D) upon which a figurine of an animal (X) is mounted. A siphon (K-L-M) connects an external wine vessel (G) to a pipe (E-F) within the float, leading to the animal's mouth. When water is drained from the main vessel via a spigot (C), the float descends, drawing wine through the siphon to spray from the animal's mouth.